What is the range of the function f(x) = -sqrt(x+3)?

2 Answers
Jun 16, 2017

Range : f(x) <=0, in interval notation: [0,-oo)

Explanation:

f(x)= -sqrt(x+3) . Output of under root is sqrt(x+3)>=0 :. f(x) <=0 .

Range : f(x) <=0 In interval notation: [0,-oo)

graph{-(x+3)^0.5 [-10, 10, -5, 5]} [Ans]

Jun 16, 2017

Range: (-oo, 0]

Explanation:

f(x) =-sqrt(x+3)

f(x) in RR forall (x+3) >=0

:. f(x) in RR forall x>=-3

f(-3) = 0 [A]

As x increases beyond all bounds f(x) -> -oo [B]

Combining results [A] and [B] the range of y is: (-oo, 0]

The range of y maybe better understood from the graph of y below.

graph{-sqrt(x+3) [-4.207, 1.953, -2.322, 0.757]}