What is the range of the function f(x)=(x-1)^2 +2?
1 Answer
Dec 23, 2017
Explanation:
"the range can be found by finding the maximum or"
"minimum turning point of "f(x)
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"
• " if "a>0" then vertex is a minimum"
• " if "a<0" then vertex is a maximum"
f(x)=(x-1)^2+2larrcolor(blue)"is in vertex form"
"with "(h,k)=(1,2)" and a>0
"hence "(1,2)" is a minimum turning point"
rArr"range is "[2,+oo)
graph{(x-1)^2+2 [-10, 10, -5, 5]}