What is the reciprocal of ${log}_{b} a$ $log_b a$ ?

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Answer 1 · 2015-04-05T03:12:25

Assuming that ${log}_{b} (a)$ $log_b(a)$ is not equal to zero its reciprocal is

$\frac{1}{{log}_{b} (a)}$ $1/log_b(a)$

A reciprocal of a number is simply $1$ $1$ over that number.

What is the reciprocal of logbalog_b a?