What is the simplest radical form of $2 \sqrt{112}$ $2sqrt112$ ?

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Answer 1 · 2017-08-15T17:43:20

$8 \sqrt{7}$ $8sqrt7$

Write the radicand as the product of its factors.
Usually prime factors is advisable, but in this case

$112 = 16 \times 7$ $112 = 16xx7$

which is very useful because $16$ $16$ is a square number.

$2 \sqrt{112}$ $2sqrt112$

$= 2 \sqrt{16 \times 7} \leftarrow$ $= 2sqrt(color(red)(16) xx7)" "larr$ find the roots if possible

$= 2 \times 4 \sqrt{7}$ $=2 xx color(red)(4)sqrt7$

$= 8 \sqrt{7}$ $=8sqrt7$

What is the simplest radical form of 2√1122sqrt112?