What is the simplest radical form of $\sqrt{\frac{2}{75}}$ $sqrt(2 / 75)$ ?

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What is the simplest radical form of $\sqrt{\frac{2}{75}}$ $sqrt(2 / 75)$ ?

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Answer 1 · 2015-07-22T01:02:06

Ifound: $\frac{1}{15} \sqrt{6}$ $1/15sqrt(6)$

Explanation:

You can rationalize:
$\sqrt{\frac{2}{75}} = \frac{\sqrt{2}}{\sqrt{75}} \cdot \frac{\sqrt{75}}{\sqrt{75}} = \frac{\sqrt{2} \sqrt{75}}{75} =$ $sqrt(2/75)=sqrt(2)/sqrt(75)*sqrt(75)/sqrt(75)=(sqrt(2)sqrt(75))/75=$
$= \frac{\sqrt{2} \sqrt{3 \cdot 25}}{75} = \frac{5}{75} \sqrt{2} \sqrt{3} = \frac{1}{15} \sqrt{6}$ $=(sqrt(2)sqrt(3*25))/75=5/75sqrt(2)sqrt(3)=1/15sqrt(6)$

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What is the simplest radical form of $\sqrt{\frac{2}{75}}$ $sqrt(2 / 75)$ ?

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What is the simplest radical form of sqrt(2 / 75)√275sqrt(2 / 75)?

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What is the simplest radical form of $\sqrt{\frac{2}{75}}$ $sqrt(2 / 75)$ ?