Question

What is the slope of a line tangent to the curve `3y^2-2x^2=1`?

Answer 1

The slope of the tangent line is `(2x)/(3y)`.

Explanation:

We have:

`6y(dy/dx) - 4x = 0`

`6y(dy/dx) = 4x`

`dy/dx= (4x)/(6y)`

`dy/dx = (2x)/(3y)`

Hopefully this helps!