What is the slope of the line passing through the following points: (7/10,-1) , (-1/5, -1/5)(710,−1),(−15,−15)?

1 Answer
Nallasivam V
Apr 14, 2018

Slope m=-2/3m=−23

Explanation:

Given -

x_1=7/10x1=710
y_1=-1y1=−1
x_2=- 1/5x2=−15
y_2=- 1/5y2=−15

Slope m=(y_2-y_1)/(x_2-x_1)=(-1/5-(-1))/(-1/5-7/10)=((-1+5)/5)/((-5-7)/10)=(4/5)/((-12)/10)m=y2−y1x2−x1=−15−(−1)−15−710=−1+55−5−710=45−1210
=4/5 -:(-12)/10=4/5 xx 10/(-12)=-40/60=-2/3=45÷−1210=45×10−12=−4060=−23

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