What is the slope of the line $y - 4 = \frac{1}{4} (x + 2)$ $y-4 = 1/4(x+2)$ ?

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What is the slope of the line $y - 4 = \frac{1}{4} (x + 2)$ $y-4 = 1/4(x+2)$ ?

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Answer 1 · 2016-01-02T14:16:49

$m = \frac{1}{4}$ $m=1/4$

Explanation:

The equation of the line in slope-intercept form is

$y = m x + b$ $y=mx+b$

Arrange your equation to match that form

$y - 4 = \frac{1}{4} x + \frac{1}{2}$ $y - 4 = 1/4 x + 1/2$

$y = \frac{1}{4} x + \frac{1}{2} + 4$ $y=1/4x+1/2 + 4$

$y = \frac{1}{4} x + \frac{9}{2}$ $y = 1/4x + 9/2$

Compare this with the slope-intercept form to get

$slope = m = \frac{1}{4}$ $"slope" = m = 1/4$

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What is the slope of the line $y - 4 = \frac{1}{4} (x + 2)$ $y-4 = 1/4(x+2)$ ?

1 Answer

Explanation:

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What is the slope of the line y-4 = 1/4(x+2)y−4=14(x+2)y-4 = 1/4(x+2)?

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What is the slope of the line $y - 4 = \frac{1}{4} (x + 2)$ $y-4 = 1/4(x+2)$ ?