What is the solution set for x^2 - 2x + 5 = 0?

1 Answer
Nallasivam V
Aug 10, 2015

x =(2+ sqrt( - 16))/ (2)
x =(2- sqrt( - 16))/ (2)

Explanation:

Since ------- (-2)^2 - (4 xx1 xx 5) < 0, x has imaginary roots

x =(-b+- sqrt(b^2 - (4ac)))/ (2a)
x =(-(-2)+- sqrt((-2)^2 - (4xx1xx5)))/ (2xx1)
x =(-(-2)+- sqrt(4 - 20))/ (2)
x =(2+ sqrt( - 16))/ (2)
x =(2- sqrt( - 16))/ (2)

Related questions
See all questions in Comparing Methods for Solving Quadratics
Impact of this question
5237 views around the world
You can reuse this answer
Creative Commons License