What is the sqrt145 in simplest radical form?

2 Answers
Dec 19, 2017

\sqrt{145}=\sqrt{5*29}

5 and 29 are both prime numbers , so the simplest form of \sqrt{145} is \sqrt{145}

Dec 19, 2017

Simplest form = sqrt(145)

approx 12.042

Explanation:

We must recall our laws of radicals:

sqrt(a*b*c) = sqrt(a)*sqrt(b)*sqrt(c)

So the next thing to do is to find the prime factors of 145

145 = 5 * 29

=> sqrt(145) = sqrt(5)*sqrt(29)

But we see sqrt(5) and sqrt(29) are both in the simplest form as they are both prime, cant be factored any more

Hence sqrt(145) is in its simplest form already

sqrt(145) approx 12.042