What is the $sqrt145$ in simplest radical form?

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Answer 1 · 2017-12-19T21:22:03

$\sqrt{145}=\sqrt{5*29}$

5 and 29 are both prime numbers , so the simplest form of $\sqrt{145}$ is $\sqrt{145}$

Answer 2 · 2017-12-19T21:25:41

Simplest form = $sqrt(145)$

$approx 12.042$

We must recall our laws of radicals:

$sqrt(a*b*c) = sqrt(a)*sqrt(b)*sqrt(c)$

So the next thing to do is to find the prime factors of $145$

$145 = 5 * 29$

$=> sqrt(145) = sqrt(5)*sqrt(29)$

But we see $sqrt(5)$ and $sqrt(29)$ are both in the simplest form as they are both prime, cant be factored any more

Hence $sqrt(145)$ is in its simplest form already

$sqrt(145) approx 12.042$

What is the sqrt145sqrt145 in simplest radical form?