What is the square root of 24?

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What is the square root of 24?

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Answer 1 · 2018-03-24T05:36:10

$2 \sqrt{6}$ $2sqrt(6)$

Explanation:

Given: $\sqrt{24}$ $sqrt(24)$

We split it into the following:

$= \sqrt{4 \cdot 6}$ $=sqrt(4*6)$

Now, we use the radical rule which states that, $\sqrt{a b} = \sqrt{a} \cdot \sqrt{b}, a, b > 0$ $sqrt(ab)=sqrt(a)*sqrt(b),a,b>0$ .

So, we get,

$= \sqrt{4} \cdot \sqrt{6}$ $=sqrt(4)*sqrt(6)$

$= 2 \sqrt{6}$ $=2sqrt(6)$

Answer 2 · 2018-03-24T05:37:03

$\sqrt{24} = 2 \sqrt{6}$ $sqrt(24)=2sqrt(6)$

Explanation:

We should try to reduce $\sqrt{24}$ $sqrt(24)$ to the root of a number with a perfect square multiplied by some other whole number.

Let's consider the factors of $24 :$ $24:$

$1, 4, 6, 8, 12, 24$ $1, 4, 6, 8, 12, 24$

Out of these, $4$ $4$ is the largest (and coincidentally, only) perfect square present.

$4 \cdot 6 = 24,$ $4*6=24,$ so we can rewrite as

$\sqrt{24} = \sqrt{4 \cdot 6} = \sqrt{4} \cdot \sqrt{6}$ $sqrt(24)=sqrt(4*6)=sqrt(4)*sqrt(6)$ as $\sqrt{a b} = \sqrt{a} \cdot \sqrt{b}$ $sqrt(ab)=sqrt(a)*sqrt(b)$

Simplify:

$\sqrt{4} \cdot \sqrt{6} = 2 \sqrt{6}$ $sqrt(4)*sqrt(6)=2sqrt(6)$

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What is the square root of 24?

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