What is the square root of (64-x^2)?

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What is the square root of (64-x^2)?

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Answer 1 · 2015-09-30T14:43:02

$\sqrt{64 - x^{2}} = \sqrt{(8 + x) (8 - x)}$ $sqrt(64-x^2)=sqrt((8+x)(8-x))$

$\sqrt{64 x^{2}} = 8 x$ $sqrt(64x^2)=8x$

Explanation:

Applying the rule for difference of 2 squares, we may write this as

$\sqrt{64 - x^{2}} = \sqrt{(8 + x) (8 - x)}$ $sqrt(64-x^2)=sqrt((8+x)(8-x))$

If the original question had to be $\sqrt{64 x^{2}}$ $sqrt(64x^2)$ then by laws of surds this would be equal to $\sqrt{64} \cdot \sqrt{x^{2}} = 8 x$ $sqrt64*sqrt(x^2)=8x$

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What is the square root of (64-x^2)?

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