What is the standard form of a line that goes through (5,4) and is perpendicular to y=54x5?

1 Answer
Apr 20, 2017

5y+4x=0

Explanation:

Since the line is perpendicular to another line with slope 54, its slope will be the negative reciprocal of the other line's slope.

Hence the slope of the line is 45. We also know it passes through (5,4).

Using

y=mx+c

we know

m (slope) =45

therefore

y=45x+c

Substituting (5,4) gives you

4=45(5)+c

c=0

Therefore

y=45x

5y=4x

5y+4x=0