What is the standard form of a polynomial $(9a^2-4-5a)-(12a-6a^2+3)$ ?

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Answer 1 · 2017-07-05T13:22:26

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$9a^2 - 4 - 5a - 12a + 6a^2 - 3$

Next, group like terms in descending order of the power of their exponents:

$9a^2 + 6a^2 - 5a - 12a - 4 - 3$

Now, combine like terms:

$(9 + 6)a^2 + (-5 - 12)a + (-4 - 3)$

$15a^2 + (-17)a + (-7)$

$15a^2 - 17a - 7$

Answer 2 · 2017-07-05T14:06:37

$15a^2-17a-7$

$(9a^2-4-5a)-(12a-6a^2+3)$

$:.=9a^2-4-5a-12a+6a^2-3$

$:.=15a^2-17a-7$

What is the standard form of a polynomial (9a^2-4-5a)-(12a-6a^2+3)(9a^2-4-5a)-(12a-6a^2+3)?