What is the the vertex of $x =-1/2(y-2)^2-4$ ?

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Answer 1 · 2016-04-11T20:27:44

vertex $=(-4,2)$

$x=-1/2(ycolor(green)(-2))^2color(red)(-4)$

Consider the $color(green)( 2)$ from $(ycolor(green)(-2))$

$y_("vertex")=(-1)xxcolor(green)(-2)=+2$

$x_("vertex")=color(red)(-4)$
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What is the the vertex of x =-1/2(y-2)^2-4 x =-1/2(y-2)^2-4 ?