What is the the vertex of $y = -12x^2 - 2x - 6$ ?

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Answer 1 · 2016-02-29T10:11:01

$(-1/12, -71/12)$

Write the equation in vertex form as follows:

y= $-12(x^2 +x/6) -6$

= $-12(x^2 +x/6+ 1/144- 1/144)-6$

= $-12(x+1/12)^2 -6+12/144$

= $-12(x+1/12)^2 -71/12$

The vertex is therefore $(-1/12, -71/12)$

What is the the vertex of y = -12x^2 - 2x - 6y = -12x^2 - 2x - 6?