What is the the vertex of $y = -12x^2 - 4x-5$ ?

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Answer 1 · 2018-05-18T18:18:45

$x = -(-4)/(2(-12)) = -1/6$
$y=-12(-1/6)^2-4(-1/6)-5 = -14/3$

$y=ax^2 + bx +c$
The vertex is the (x, y) value where $x = (-b)/(2a)$ and y = the result when you put the x you found into the equation.

What is the the vertex of y = -12x^2 - 4x-5y = -12x^2 - 4x-5?