Question

What is the the vertex of `y = -3x^2+6x-1`?

Answer 1

The `v(-1, 2)`
`x = 0; f(0) = -1`

Explanation:

Given `f(x) = y = ax^2 + bx + c " "` form of the equation
The vertex, `v(h, k)`
`h = -b/(2a); and k = f(h)`
Now `f(x) = -3x^2 + 6x - 1`
`h = - 6/(2*3) = -1; f(-1) = 2`
Thus `v(-1, 2)`

Intercept is simply -1, to find simply set `x = 0; f(0) = -1`