What is the the vertex of $y =4x^2-12x+9$ ?

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Answer 1 · 2015-12-03T05:50:04

Find vertex of y = 4x^2 - 12x + 9

x-coordinate of vertex:
$x = (-b)/(2a) = 12/8 = -3/2$
y-coordinate of vertex:
$y = y(-3/2) = 4(9/4) - 12(-3/2) + 9 = 9 + 18 + 9 = 36$

What is the the vertex of y =4x^2-12x+9y =4x^2-12x+9?