Question

What is the the vertex of `y = 6(x - 2)^2 ­- 8`?

Answer 1

`"Vertex"->(x,y)->(2,-8)`

Explanation:

The equation in this vertex form gives you the value of x for the vertex.

Consider the -2 from `(x-2)`

Apply `(-1)xx(-2)=+2`

`color(blue)(x_("vertex")=+2)`

Substitute `x=2` into the equation to find `y_("vertex")`

`y_("vertex") = 6( 2-2)^2-8`

`y_("vertex") = 6(0)^2-8`

`color(blue)(y_("vertex") = -8`
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

`color(green)("Vertex"->(x,y)->(2,-8)`