What is the the vertex of $y = {(x - 12)}^{2} + 26$ $y=(x -12)^2 + 26$ ?

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Answer 1 · 2015-11-25T23:55:57

Find vertex of $y = {(x - 12)}^{2} + 26 .$ $y = (x - 12)^2 + 26.$
Ans: Vertex (12, 26)

$y = {(x - 12)}^{2} + 26$ $y = (x - 12)^2 + 26$ .
This is the vertex form of y. Therefor the coordinates of vertex are:
vertex (12, 26)

What is the the vertex of y=(x−12)2+26y=(x -12)^2 + 26 ?