What is the the vertex of $y = x^{2} + 12 x + 14$ $y = x^2 +12x +14$ ?

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What is the the vertex of $y = x^{2} + 12 x + 14$ $y = x^2 +12x +14$ ?

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Answer 1 · 2015-12-23T15:55:29

$(- 6, - 22)$ $(-6, -22)$

Explanation:

Get the equation into vertex form by completing the square.
$y = {(x + 6)}^{2} - 36 + 14$ $y = (x+6)^2 -36 +14$
$y = {(x + 6)}^{2} - 22$ $y = (x+6)^2 -22$
There fore the vertex is the minimum value of the expression i.e. $(- 6, - 22)$ $(-6, -22)$

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What is the the vertex of $y = x^{2} + 12 x + 14$ $y = x^2 +12x +14$ ?

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What is the the vertex of y = x^2 +12x +14y=x2+12x+14y = x^2 +12x +14?

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What is the the vertex of $y = x^{2} + 12 x + 14$ $y = x^2 +12x +14$ ?