What is the the vertex of $y = x^2-14x+13$ ?

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Answer 1 · 2016-03-15T22:05:50

$(7, -36)$

$y = x^2-14x+13 = (x-7)^2-49+13 = (x-7)^2-36$

Slightly rephrasing:

$y = 1(x-7)^2+(-36)$

This is in standard vertex form:

$y = a(x-h)+k$

where $(h, k) = (7, -36)$ is the vertex and $a=1$ the multiplier.

graph{x^2-14x+13 [-15, 29.38, -44.64, -22.44]}

What is the the vertex of y = x^2-14x+13y = x^2-14x+13?