What is the the vertex of $y =-x^2-3x-6$ ?

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Answer 1 · 2018-04-10T06:51:26

$(-3/2,-3/2)$

$(-b)/(2a)$ is the $x$ coordinate at this point

$(--3)/(2xx-1)$ = $3/(-2)$

Put this value into the equation to find the $y$ value

$(-3/(-2))^2-3xx(3/(-2))-6$

= $9/4+9/4-6$ = $18/4-6$

= $-3/2$

What is the the vertex of y =-x^2-3x-6 y =-x^2-3x-6 ?