What is the the vertex of y = x^2-4x+20 ?
1 Answer
Jun 18, 2018
Explanation:
"given a parabola in "color(blue)"standard form ";ax^2+bx+c
"then the x-coordinate of the vertex is"
•color(white)(x)x_(color(red)"vertex")=-b/(2a)
x^2-4x+20" is in standard form"
"with "a=1,b=-4" and "c=20
x_("vertex")=-(-4)/2=2
"substitute this value into the equation for y-coordinate"
y_("vertex")=2^2-4(2)+20=16
color(magenta)"vertex "=(2,16)