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What is the the vertex of $y = {(x + 3)}^{2}$ $y = (x + 3)^2$ ?

1 Answer

Jan 29, 2016

vertex: $(- 3, 0)$ $(-3,0)$

Explanation:

$y = {(x + 3)}^{2}$ $y=(x+3)^2$
could be written as
$XXX y = 1 {(x - (- 3))}^{2} + 0$ $color(white)("XXX")y = color(green)(1)(x-(color(red)(-3)))^2+color(blue)(0)$

Which is of the general "vertex form"
$XXX y = k {(x - a)}^{2} + b$ $color(white)("XXX")y=color(green)(k)(x-color(red)(a))^2+color(blue)(b)$
with vertex at $(a, b)$ $(color(red)(a),color(blue)(b))$

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