What is the the vertex of $y = (x - 3) (x + 5) - x + 12$ $y = (x-3)(x+5) -x+12$ ?

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What is the the vertex of $y = (x - 3) (x + 5) - x + 12$ $y = (x-3)(x+5) -x+12$ ?

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Answer 1 · 2016-03-03T01:39:24

$(- \frac{1}{2}, - \frac{13}{4})$ $(-1/2, -13/4)$

Explanation:

The equation $x - α)^{2}$ $x-alpha)^2$ = $4 a (y - β)$ $4 a (y-beta)$ represents the parabola with vertex at $(α, β)$ $(alpha, beta)$
The focus is at $(α, β + a)$ $(alpha, beta+a)$ .
Our equation is equivalent to ${(x + \frac{1}{2})}^{2}$ $(x+1/2)^2$ = $4 (\frac{1}{4}) (y + \frac{13}{4})$ $4(1/4)(y+13/4)$
Vertex is $(- \frac{1}{2}, - \frac{13}{4})$ $(-1/2, -13/4)$
Focus is $(- \frac{1}{2}, - 3)$ $(-1/2, -3)$ .

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What is the the vertex of $y = (x - 3) (x + 5) - x + 12$ $y = (x-3)(x+5) -x+12$ ?

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Explanation:

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Science

Math

Humanities

... and beyond

What is the the vertex of y=(x−3)(x+5)−x+12y = (x-3)(x+5) -x+12?

1 Answer

Explanation:

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What is the the vertex of $y = (x - 3) (x + 5) - x + 12$ $y = (x-3)(x+5) -x+12$ ?