What is the the vertex of y=(x - 8)^2 + 48 ?
1 Answer
Jan 22, 2017
Explanation:
The equation of a parabola in
color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
where (h ,k) are the coordinates of the vertex and a, is a constant.
"For " y=(x-8)^2+48
a=1,h=8" and " k=48
rArr"vertex "=(8,48)
graph{(x-8)^2+48 [-160, 160, -80, 80]}