What is the the vertex of y=(x - 8)^2 + 48 ?

1 Answer
Jan 22, 2017

(8,48)

Explanation:

The equation of a parabola in color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
where (h ,k) are the coordinates of the vertex and a, is a constant.

"For " y=(x-8)^2+48

a=1,h=8" and " k=48

rArr"vertex "=(8,48)
graph{(x-8)^2+48 [-160, 160, -80, 80]}