Question

What is the trigonometric form of `5+6i`?

Answer 1

`sqrt61[cos(0.876) + isin(0.876)]`

Explanation:

using the following formulae.

`• r^2 = x^2 + y^2`

`• theta = tan^-1 (y/x)`

here x = 5 and y = 6

`r^2 = 5^2+6^2 = 25+36 = 61 rArr r = sqrt61`

`theta = tan^-1(6/5) ≈ 0.876 " radians "`

hence the trig. form of 5 + 6i is:

`sqrt61[ cos(0.876) + isin(0.876)]`