Question

What is the trigonometric form of `(-6-i)`?

Answer 1

`sqrt37(cos(0.165) + isin(0.165))`

Explanation:

Using the following formulae:

`• r^2 = x^2 + y^2`

`• theta = tan^-1(y/x)`

here x = -6 and y = -1

`r^2 = (-6)^2+(-1)^2 = 37 rArr r = sqrt37`

and `theta = tan^-1((-1)/(-6)) = tan^-1(1/6) ≈0.165 " radians "`

`rArr (-6-i) = sqrt37(cos(0.165) + isin(0.165))`