What is the trigonometric form of $e^( ( 5 pi)/12 i )$ ?

Question

1610 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-23T02:22:52

$e^((5pi)/(12) i) = cos( (5pi)/12)+isin((5pi)/12)$

$e^(itheta)=costheta+isintheta$
$theta=(5pi)/12$
$e^((5pi)/(12) i) = cos( (5pi)/12)+isin((5pi)/12)$

What is the trigonometric form of e^( ( 5 pi)/12 i ) e^( ( 5 pi)/12 i ) ?