What is the value of $\frac{1}{3} x^{3} + 5.4 y$ $1/3x^3+5.4y$ when $x = 3$ $x=3$ and $y = 2$ $y=2$ ?

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What is the value of $\frac{1}{3} x^{3} + 5.4 y$ $1/3x^3+5.4y$ when $x = 3$ $x=3$ and $y = 2$ $y=2$ ?

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Answer 1 · 2018-06-23T11:11:49

$19.8$ $19.8$

Explanation:

$substitute the given values for x and y into the expression$ $"substitute the given values for x and y into the expression"$
$and evaluate$ $"and evaluate"$

$= \frac{1}{3} \times {(3)}^{3} + 5.4 \times 2$ $=1/3xx(color(red)(3))^3+5.4xxcolor(magenta)(2)$

$=1/cancel(3)^1xxcancel(27)^9+10.8$

$=9+10.8$

$=19.8$

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What is the value of $\frac{1}{3} x^{3} + 5.4 y$ $1/3x^3+5.4y$ when $x = 3$ $x=3$ and $y = 2$ $y=2$ ?

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