What is the value of $cosh (ln 3)$ $cosh(ln3)$ ?

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Answer 1 · 2016-11-08T17:32:34

$cosh (ln 3) = \frac{5}{3}$ $cosh(ln3)=5/3$

$Coshx=1/2(e^x+e^-x) AAx inRR$

so

$cosh(ln3)=1/2(e^(ln3)+e^-ln3)$

$cosh(ln3)=1/2(e^(ln3)+e^ln(1/3))$

$cosh(ln3)=1/2(3+1/3)=1/2(10/3)$

$cosh(ln3)=5/3$

What is the value of cosh(ln3)cosh(ln3)cosh(ln3)?