What is the value of the exponential expression $(- 2 a^{- 2} b^{4}) (3 a^{2} b^{- 5})$ $(-2a^-2 b^4)(3a^2 b^-5)$ ?

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Answer 1 · 2018-06-27T14:24:24

Multiply the numbers together then the letters

$- 6 a^{0} b^{- 1}$ $-6a^0b^(-1)$

$- 6 b^{- 1} or - \frac{6}{b}$ $-6b^-1 or -6/b$

Answer 2 · 2018-06-27T15:06:36

$- \frac{6}{b}$ $-6/b$

$(- 2 a^{- 2} b^{4}) (3 a^{2} b^{- 5})$ $(-2a^-2b^4)(3a^2b^-5)$

$:.=(-2*1/a^2*b^4)(3a^2*1/b^5)$

$:.=(-6cancel(b^4))/cancel(a^2)^1*cancel(a^2)^1/cancel(b^5)^b$

$:.=-6/b$

What is the value of the exponential expression (-2a^-2 b^4)(3a^2 b^-5) (−2a−2b4)(3a2b−5)(-2a^-2 b^4)(3a^2 b^-5) ?