What is the value of the exponential expression #(-2a^-2 b^4)(3a^2 b^-5) #?

Question

1531 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-27T14:24:24

Multiply the numbers together then the letters

#-6a^0b^(-1)#

#-6b^-1 or -6/b#

Answer 2 · 2018-06-27T15:06:36

#-6/b#

#(-2a^-2b^4)(3a^2b^-5)#

#:.=(-2*1/a^2*b^4)(3a^2*1/b^5)#

#:.=(-6cancel(b^4))/cancel(a^2)^1*cancel(a^2)^1/cancel(b^5)^b#

#:.=-6/b#