What is the variance of {8, 19, 10, 0, 1, 0}?

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Answer 1 · 2016-03-15T09:45:04

#sigma^2=428/9=47.5556#

From the given: #n=6#

We solve for arithmetic mean first.

#barx=(8+19+10+0+1+0)/6=38/6=19/3#

The formula for variance of ungrouped data is

#sigma^2=(sum (x-barx)^2)/n#

#sigma^2=((8-19/3)^2+(19-19/3)^2+(10-19/3)^2+(0-19/3)^2+(1-19/3)^2+(0-19/3)^2)/6#

#sigma^2=428/9=47.5556#

God bless.... I hope the explanation is useful.