What is the vertex form of $y= -25x^2 + 8x - 13$ ?

Question

1669 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-28T12:32:49

Vertex form of equation is $y = -25 (x-0.16)^2-12.36$

$y = -25 x^2+8 x -13$ or

$y = -25 (x^2-8/25 x) -13$ or

$y = -25 {x^2-8/25 x + (4/25)^2}+25 *16/625 -13$ or

$y = -25 (x-4/25)^2+16/25 -13$ or

$y = -25 (x-4/25)^2-309/25$ or

$y = -25 (x-0.16)^2-12.36 :.$ Vertex is at

$(0.16 , -12.36)$ and vertex form of equation is

$y = -25 (x-0.16)^2-12.36$ [Ans]

What is the vertex form of y= -25x^2 + 8x - 13 y= -25x^2 + 8x - 13 ?