What is the vertex of $x = –2(y– 3)^2 - 2$ ?

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Answer 1 · 2016-06-24T15:22:48

$"Vertex "->(x,y)=(-2,3)$

This equation is in vertex form

You deal with this the same way as you would if the x was where the y is. The only difference instead of $x=(-1)xx(-3)$ you have

$y=(-1)xx(-3)$ where the -3 comes from $(y-3)^2$

The value of $x$ you can read off directly as the constant -2

$"Vertex "->(x,y)=(-2,3)$

Tony B

What is the vertex of x = –2(y– 3)^2 - 2x = –2(y– 3)^2 - 2?