What is the vertex of $x = {(2 y + 3)}^{2} - 2$ $x = (2y + 3)^2 - 2$ ?

Question

What is the vertex of $x = {(2 y + 3)}^{2} - 2$ $x = (2y + 3)^2 - 2$ ?

1 Answer

Impact of this question

1549 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-19T17:03:49

$(- 2, - \frac{3}{2})$ $(-2, -3/2)$

Explanation:

The given equation can be rewritten in a suitable form as follows:

$x = 4 {(y + \frac{3}{2})}^{2} - 2$ $x= 4(y+3/2)^2 -2$

$\frac{1}{4} x = {(y + \frac{3}{2})}^{2} - \frac{1}{2}$ $1/4 x = (y+3/2)^2 -1/2$ .

$\frac{1}{4} (x + 2) = {(y + \frac{3}{2})}^{2}$ $1/4 ( x+2)= (y+3/2)^2$ . The vertex may be read from this equation. It is $(- 2, - \frac{3}{2})$ $(-2, -3/2)$

Science

Math

Humanities

... and beyond

What is the vertex of $x = {(2 y + 3)}^{2} - 2$ $x = (2y + 3)^2 - 2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the vertex of x = (2y + 3)^2 - 2 x=(2y+3)2−2 x = (2y + 3)^2 - 2 ?

1 Answer

Explanation:

Related questions

Impact of this question

What is the vertex of $x = {(2 y + 3)}^{2} - 2$ $x = (2y + 3)^2 - 2$ ?