What is the vertex of # y= -12x^2-4x-2?

1 Answer
Binayaka C.
Apr 25, 2017

The vertex is at ( -1/6 , -5/3)(−16,−53)

Explanation:

y=-12 x^2-4 x-2y=−12x2−4x−2. Comparing with standard equation ax^2+bx+cax2+bx+c we get a= -12 , b= -4 ,c= -2a=−12,b=−4,c=−2
xx co-ordinate of vertex is -b/(2 a) = -4/(2* -12) = -1/6−b2a=−42⋅−12=−16

Then, yy co-ordinate of vertex is y = -12(-1/6)^2-4(-1/6)-2= -5/3y=−12(−16)2−4(−16)−2=−53
The vertex is at ( -1/6 , -5/3)(−16,−53) graph{-12x^2-4x-2 [-20, 20, -10, 10]}

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