What is the vertex of $y = 2(x - 3)^2 + 1$ ?

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Answer 1 · 2017-04-26T23:42:26

The vertex is $(3,1)$

When given and equation of the form:

$y = a(x-h)^2+k$

The vertex is the point $(h,k)$

Given: $y = 2(x - 3)^2 + 1$

The vertex is $(3,1)$

What is the vertex of y = 2(x - 3)^2 + 1 y = 2(x - 3)^2 + 1 ?