What is the vertex of $y=2 (x-3)^2+4$ ?

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Answer 1 · 2015-10-23T00:54:47

Vertex is $(3, 4)$

The given equation is in the vertex form.

$y=a(x-h)^2+k$

In this case the x co-ordinate of the vertex is $-(h)$ and y co-ordinate of the vertex is $k$ .

Apply this to our case
x co-ordinate of the vertex is $-(-3)=3$
y co-ordinate of the vertex is $4$ .

Vertex is $(3, 4)$

What is the vertex of y=2 (x-3)^2+4y=2 (x-3)^2+4?