Question

What is the vertex of `y=2 (x-3)^2+4`?

Answer 1

Vertex is `(3, 4)`

Explanation:

The given equation is in the vertex form.

`y=a(x-h)^2+k`

In this case the x co-ordinate of the vertex is `-(h)` and y co-ordinate of the vertex is `k`.

Apply this to our case
x co-ordinate of the vertex is `-(-3)=3`
y co-ordinate of the vertex is `4`.

Vertex is `(3, 4)`