What is the vertex of #y=2(x-3)^2+4#?
1 Answer
Jan 4, 2016
Explanation:
This is in vertex form. Vertex form is a handy way of writing quadratic equations so that their vertices are evident from the equation itself and require no algebra to find.
Vertex form is:
#y=a(x-h)^2+k#
When
The only tricky thing to watch out for is the
Thus,
#h=3#
#k=4#
The vertex is at
graph{2(x-3)^2+4 [-8.02, 14.48, -1.53, 9.72]}