What is the vertex of #y=2(x-3)^2+4#?

1 Answer
Jan 4, 2016

#(3,4)#

Explanation:

This is in vertex form. Vertex form is a handy way of writing quadratic equations so that their vertices are evident from the equation itself and require no algebra to find.

Vertex form is:

#y=a(x-h)^2+k#

When #(h,k)# is the vertex of the parabola.

The only tricky thing to watch out for is the #x#-coordinate. In vertex form, it's written as #-h#, so the actual #x#-coordinate #h# will be the opposite of whatever is written inside the square term.

Thus,

#h=3#
#k=4#

The vertex is at #(3,4)#.

graph{2(x-3)^2+4 [-8.02, 14.48, -1.53, 9.72]}