What is the vertex of y= 2(x-5)^2-5x^2-x-1?

1 Answer
Roella W.
Jan 20, 2016

The vertex is (-7/2, 343/4)

Explanation:

First expand the equation to get rid of the brackets and into standard form. The expression can then be rearranged into vertex to identify the vertex.

y = 2(x^2 -10x +25) - 5x^2 - x -1
y= -3x^2 -21x +49
y = -3(x^2 +7x) +49

y = -3(x+7/2)^2 +147/4 + 49
y = -3(x+7/2)^2 +343/4

The vertex is (-7/2, 343/4)

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