What is the vertex of $y= 2x^2 - 18x -6$ ?

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Answer 1 · 2016-03-02T14:30:46

$x_("vertex")=+9/2$
I will let you work out $y_("vertex")$ by substitution

Write as: $" "y=2(x^2-18/2 x) -6$

Apply $" "(-1/2)xx(-18/2) = + 9/2$

$x_("vertex")=+9/2$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~
To derive $y_("vertex")$ substitute $x=9/2$ into the original equation and solve for y

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What is the vertex of y= 2x^2 - 18x -6y= 2x^2 - 18x -6?