What is the vertex of $y = - 2 x^{2} + 2 x + 9$ $y= -2x^2 + 2x + 9$ ?

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What is the vertex of $y = - 2 x^{2} + 2 x + 9$ $y= -2x^2 + 2x + 9$ ?

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Answer 1 · 2018-06-13T20:10:27

$vertex = (\frac{1}{2}, \frac{19}{2})$ $"vertex "=(1/2,19/2)$

Explanation:

$given a quadratic in standard form$ $"given a quadratic in standard form"$

$y = a x^{2} + b x + c; a \neq 0$ $y=ax^2+bx+c;a!=0$

$then the x-coordinate of the vertex is$ $"then the x-coordinate of the vertex is"$

$∙ x x_{vertex} = - \frac{b}{2 a}$ $•color(white)(x)x_(color(red)"vertex")=-b/(2a)$

$y = - 2 x^{2} + 2 x + 9 is in standard form$ $y=-2x^2+2x+9" is in standard form"$

$with a = - 2, b = 2 and c = 9$ $"with "a=-2,b=2" and "c=9$

$x_{vertex} = - \frac{2}{- 4} = \frac{1}{2}$ $x_("vertex")=-2/(-4)=1/2$

$substitute this value into the equation for y$ $"substitute this value into the equation for y"$

$y_{vertex} = - 2 {(\frac{1}{2})}^{2} + 2 (\frac{1}{2}) + 9 = \frac{19}{2}$ $y_("vertex")=-2(1/2)^2+2(1/2)+9=19/2$

$vertex = (\frac{1}{2}, \frac{19}{2})$ $color(magenta)"vertex "=(1/2,19/2)$

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What is the vertex of $y = - 2 x^{2} + 2 x + 9$ $y= -2x^2 + 2x + 9$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

What is the vertex of y= -2x^2 + 2x + 9 y=−2x2+2x+9y= -2x^2 + 2x + 9 ?

1 Answer

Explanation:

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What is the vertex of $y = - 2 x^{2} + 2 x + 9$ $y= -2x^2 + 2x + 9$ ?