What is the vertex of $y = 2 x^{2} - 8 x + 6$ $y= 2x^2 - 8x + 6$ ?

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What is the vertex of $y = 2 x^{2} - 8 x + 6$ $y= 2x^2 - 8x + 6$ ?

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Answer 1 · 2016-01-10T22:10:03

Vertex (2, -2)

Explanation:

x-coordinate of vertex:
$x = - \frac{b}{2 a} = \frac{8}{4} = 2$ $x = -b/(2a) = 8/4 = 2$
y-coordinate of vertex:
$y (2) = 2 (4) - 8 (2) + 6 = 8 - 16 + 6 = - 2$ $y(2) = 2(4) - 8(2) + 6 = 8 - 16 + 6 = -2$

Vertex (2, -2)

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What is the vertex of $y = 2 x^{2} - 8 x + 6$ $y= 2x^2 - 8x + 6$ ?

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Explanation:

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Science

Math

Humanities

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What is the vertex of y= 2x^2 - 8x + 6y=2x2−8x+6y= 2x^2 - 8x + 6?

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Explanation:

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What is the vertex of $y = 2 x^{2} - 8 x + 6$ $y= 2x^2 - 8x + 6$ ?