What is the vertex of y= 3(x+5)^2-30x-25 ? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Cem Sentin May 24, 2018 50 Explanation: y=3*(x+5)^2-30x-25 =3*(x^2+10x+25)-30x-25 =3x^2+30x+75-30x-25 =3x^2+50 Thus, vertex of y is 50 Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph y=x^2-2x+3? How do you know if y=16-4x^2 opens up or down? How do you find the x-coordinate of the vertex for the graph 4x^2+16x+12=0? See all questions in Quadratic Functions and Their Graphs Impact of this question 1626 views around the world You can reuse this answer Creative Commons License