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What is the vertex of $y = 3 x^{2} - 300$ $y= 3x^2 − 300$ ?

1 Answer

Sep 3, 2017

Vertex at $(x, y) = (0, - 300)$ $(x,y)=(0,-300)$

Explanation:

Given $y = 3 x^{2} - 300$ $y=3x^2-300$

We can re-write this in the vertex form
$XXX y = m {(x - a)}^{2} + b$ $color(white)("XXX")y=color(green)m(x-color(red)a)^2+color(blue)b$
for a parabola with vertex at $(x, y) = (a, b)$ $(x,y)=(color(red)a,color(blue)b)$

In this case
$XXX y = 3 {(x - 0)}^{2} + (- 300)$ $color(white)("XXX")y=color(green)3(x-color(red)0)^2+color(blue)(""(-300))$
for a parabola with vertex at $(x, y) = (0, - 300)$ $(x,y)=(color(red)0,color(blue)(-300))$

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