What is the vertex of y= -3x^2+4x-3y=−3x2+4x−3?

1 Answer
Nallasivam V
Dec 9, 2015

Vertex is (2/3, -1 2/3)(23,−123)

Explanation:

Given -

y=-3x^2+4x-3y=−3x2+4x−3

x=(-b)/(2a)=(-4)/(2 xx -3)=(-4)/(-6)=2/3x=−b2a=−42×−3=−4−6=23

y = -3(2/3)^2+4(2/3)-3y=−3(23)2+4(23)−3
y = -3(4/9)+4(2/3)-3y=−3(49)+4(23)−3
y = (-12)/9+8/3-3=-1 2/3y=−129+83−3=−123

Vertex is (2/3, -1 2/3)(23,−123)

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