What is the vertex of $y= 3x^2+8x-7$ ?

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Answer 1 · 2017-04-29T11:17:38

Vertex is at $(-1 1/3, -12 1/3)$

$y = 3x^2+8x-7$ . Comparing with standard equation $y = ax^2+bx+c$ we get here $a=3 , b=8 , c= -7$

x co-ordinate of vertex is $-b/(2a) or - 8/(2*3) = -4/3 = -1 1/3$ .

Putting the value of $x= -4/3$ we get y co-ordinate of vertex as

$y= 3* (-4/3)^2 +8*( -4/3) -7 = 16/3-32/3 -7=-16/3-7 =-37/3 = -12 1/3$

Vertex is at $(-1 1/3, -12 1/3)$ [Ans]

What is the vertex of y= 3x^2+8x-7 y= 3x^2+8x-7?